# Cafe turns its Wifi password into a maths equations and people are stumped

One man was visiting his local Thai restaurant and asked Reddit for some help to get the password

Wifi passwords are never known for their simplicity but one restaurant in America is taking it that one step too far.

Sharing it on Reddit, a visitor went to Yaya’s Thai, in San Antonio, Texas and was baffled when he read the details to get on the venue’s internet.

He was faced with a tough maths equation that he needed to solve to get his hands on the Wifi password, and found himself pretty stumped.

The only choice he had was to share the equation on the popular internet forum Reddit, to give maths whizzes the chance to get the password for him.

It’s not just this Thai restaurant that is confusing visitors though, as reported by CGTN, a Chinese University was under a lot of scrutiny for asking students to solve a calculus equation to get the password.

But why? Speaking to Beijing News, a member of PR staff said: “It aims at promoting the charm of higher mathematics and encouraging the freshmen to work hard.”

So, what’s the excuse for this Thai restaurant? Well, it’s not entirely clear, but one thing is for sure, it was definitely a talking point.

One user tried to crack the code and said: “This looks a lot like a summation of a binomial probability density function. I strongly doubt the divider between N/m should even be there.

“It would then be equivalent to having a number of successes of at least half of the attempts made, statistically, with a success probability of 25%. The answer depends on the number of attempts though.

“Try password ‘binomial’ or ‘Binomial’ or something like that.”

Things actually got pretty heated in the comments, with many users disagreeing with each others theories. Others saw the funnier side.

Trying to make light of the situation, another user said: “The REAL answer to this problem is that they don’t even have wifi.”

If you really want to have your mind blown, read this response from user ‘Real_John_C_Reilly:

“The first term in the summation should be a combination not a fraction if this is a binomial distribution.

“In that case (N N/2) = N!/((N/2)!2), and, (N N) = 1. The first term in the summation expansion is (N N/2)* (3/16)N/2 and the last term is (1/4)N. I’d simplify the addition of the two terms: (1/4)N * [ N!/((N/2)!)2) * 3N/2 + 1]”

“I think this answer suffices if N/2 and N are consecutive. But if that were the case N=2 so the answer would be (7/16).

“Also this assumes a LOT, due mostly to how vague the q is, and is also primarily based off the original assumption the first term in the summation was a combination and not a fraction.

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